Chapter 39, Venus Video Solutions, Pathways to Astronomy

Problem 1

Venus's atmosphere contains about $4.6 \times 10^{20} \mathrm{kg}$ of carbon dioxide $\left(\mathrm{CO}_{2}\right)$. If all of the oxygen atoms in the $\mathrm{CO}$, were combined with hydrogen to make water $\left(\mathrm{H}_{2} \mathrm{O}\right)$ instead of carbon dioxide, what would the total mass of water be? (Note:Hydrogen has an atomic mass of $1 ;$ carbon, $12 ;$ oxygen, $16 .$ How does this compare to the mass of Earth's oceans, about $1.4 \times 10^{21} \mathrm{kg} ?$

Abhishek Jana

Numerade Educator

03:23

Problem 2

From your answer to problem $1,$ how deep an ocean would this water produce if it were the same depth everywhere on the surface? (Note that $1000 \mathrm{kg}$ of water fills a volume of 1 cubic meter.)

Arpit Gupta

Numerade Educator

01:09

Problem 3

Suppose the Earth's spin slowed down until there were just 180 days in a year. Compare the length of a sidereal and a solar day in this new situation. (Do not redefine units of time- just express them in terms of our current hours, minutes, and seconds.

Rodger Claar

Numerade Educator

01:08

Problem 3

One city is at a longitude of $78^{\circ} \mathrm{E}$ while a second on is at $95^{\circ} \mathrm{W}$ How many hours will pass between a star crossing the meridian in the first city and in the second? If the time zone of each city is based on the closest longitude that is a multiple of $15^{\circ}$ and the star passes overhead in the first city exactly at midnight, what time (by the clock) will it pass over the second city?

Dominador Tan

Numerade Educator

01:09

Problem 4

Rodger Claar

Numerade Educator

00:49

Problem 5

What is your longitude, and what is the longitude of the center of the nearest time zone? Calculate what time the Sun should, on average, cross your own meridian, assuming that the Sun crosses the meridian at exactly 12: 00 at the center of your time
zone

Chris Johnson

Numerade Educator

00:49

Problem 6

Chris Johnson

Numerade Educator