D. B. Singh
ISBN #9789313195481
1st Edition
4,709 Questions
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Two absolute scales $A$ and $B$ have triple points of water defined to be $200 A$ and $350 B$. What is the relation between $T_{A}$ and $T_{B} ?$ [NCERT] (a) $\frac{T_{A}}{T_{B}}=\frac{4}{7}$ (b) $\frac{T_{A}}{T_{B}}=\frac{3}{7}$ (c) $\frac{T_{A}}{T_{B}}=\frac{7}{3}$ (d) $\frac{T_{A}}{T_{B}}=\frac{7}{4}$
A faulty thermometer has its fixed points marked 5 and 95 . When this thermometer reads 68 , the correct temperature in celsius is (a) $68^{\circ} \mathrm{C}$ (b) $70^{\circ} \mathrm{C}$ (c) $66^{\circ} \mathrm{C}$ (d) $72^{\circ} \mathrm{C}$
The Fahrenheit and Kelvin scales of temperature will give the same reading at (a) $-40$ (b) 313 (c) 574,25 (d) $732.75$
An amount of water of mass $20 \mathrm{~g}$ at $0^{\circ} \mathrm{C}$ is mixed with 40 $\mathrm{g}$ of water at $10^{\circ} \mathrm{C}$, final temperature of the mixture is (a) $5^{\circ} \mathrm{C}$ (b) $0^{\circ} \mathrm{C}$ (c) $20^{\circ} \mathrm{C}$ (d) $6.66^{\circ} \mathrm{C}$
The graph between two temperature scales $A$ and $B$ is shown in figure. Between upper fixed point and lower point there are 150 equal division on scale $A$ and 100 on scale $B$. The relationship for conversion between the two scales is given by [NCERT Exemplar] (a) $\frac{t_{A}-180}{100}=\frac{t_{B}}{150}$ (b) $\frac{t_{A}-30}{150}=\frac{t_{B}}{100}$ (c) $\frac{t_{B}-180}{150}=\frac{t_{A}}{100}$ (d) $\frac{t_{B}-40}{100}=\frac{t_{A}}{180}$