STEP-BY-STEP ANSWER:
Step 1: Differentiate x = sec t with respect to t: dx/dt = sec t tan t, and differentiate y = tan t: dy/dt = sec² t.
Step 2: At t = π/4, compute dx/dt = sec(π/4) tan(π/4) = √2·1 = √2 and dy/dt = sec²(π/4) = 2.
Step 3: Compute the slope of the tangent: dy/dx = (dy/dt)/(dx/dt) = 2/√2 = √2.
Step 4: Find the coordinates at t = π/4: x = sec(π/4) = √2, y = tan(π/4) = 1.
Step 5: Write the equation of the tangent line using point-slope form: y − 1 = √2 (x − √2).
Final Answer: The tangent line is given by y − 1 = √2 (x − √2).