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0:00

Kyle I.

Using Models Use the model given to answer the questions about the object or process being modeled. The distance $d$ (in mi) driven by a car traveling at a speed of $v$ miles per hour for $t$ hours is given by $$d=v t$$ If the car is driven at 70 milh for 3.5 $\mathrm{h}$ , how far has it traveled?

01:15

Jinseop S.

$3-12=$ Using Models Use the model given to answer the questions about the object or process being modeled. The sales tax $T$ in a certain county is modeled by the formula $T=0.06 x .$ Find the sales tax on an item whose price is $\$ 120 .$

00:57

Amy J.

The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.

Kelli P.

Making Models : Write an algebraic formula that models the given quantity. 15. The cost $C$ of purchasing $x$ gallons of gas at $\$ 3.50$ a gallon

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Let's look at the expression five minus a modest one plus C minus six. A squared plus a squared. Now I can automatically see I don't have any parentheses, so we're not gonna be doing any distributive property in this problem. We do have several terms. So we do wanna look for any light terms that we can combine. I noticed with the five, it's just a constant doesn't have available, so I can combine it with any numbers that also don't have available. In this case, that's negative. One also have to terms with a square. I have a negative six a squared and I have a positive A squared notice. I did put the signs in front of them in the box because that's gonna help me remember what operation I need to use to solve this. So all I have left that doesn't have a circle or a box around it is a negative A and a positive See in these cases now, either one of those have a like term anywhere else in the problem. So we're not going to combine those with anything will bring them down when the time comes. We want to combine any variables with exponents first. So let's go ahead and combine our six a squared and our positive A squared. Well, since this was negative and this was positive, we're gonna combine and we're gonna have negative five a square. Now let's combine. Let's look at our other variables. Well, since we use the A, let's go ahead and bring down Just are rigged A that doesn't have a exponents so minus a and let's bring down our other variable, which is a positive C. I did bring down the signs that were in front of them so that they do keep those signs. Now we've already brought down everything that has a variable. So let's combine anything that doesn't which in this case is five and negative. One and five minus one is four, and it's positive for, so our solution is negative. Five. A squared minus a plus C plus four

Linear Equations and Functions

Linear Equations and Inequalities

Matrices and Determinants

Quadratic Equations

Applications of Trigonometric Functions

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