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Michigan State University

University of Michigan - Ann Arbor

03:34

Kyle I.

Using Models Use the model given to answer the questions about the object or process being modeled. The distance $d$ (in mi) driven by a car traveling at a speed of $v$ miles per hour for $t$ hours is given by $$d=v t$$ If the car is driven at 70 milh for 3.5 $\mathrm{h}$ , how far has it traveled?

0:00

Kelli P.

Making Models : Write an algebraic formula that models the given quantity. 15. The cost $C$ of purchasing $x$ gallons of gas at $\$ 3.50$ a gallon

06:25

Daniel P.

Using Models Use the model given to answer the questions about the object or process being modeled. The portion of a floating iceberg that is below the water sur- face is much larger than the portion above the surface. The total volume $V$ of an iceberg is modeled by $$V=9.5 S$$ where $S$ is the volume showing above the surface. (a) Find the total volume of an iceberg if the volume show- ing above the surface is 4 $\mathrm{km}^{3}$ . (b) Find the volume showing above the surface for an ice- berg with total volume 19 $\mathrm{km}^{3}$ .

00:55

Taylor S.

Using Models Use the model given to answer the questions about the object or process being modeled. The volume $V$ of a cylindrical can is modeled by the formula $$V=\pi r^{2} h$$ where $r$ is the radius and $h$ is the height of the can. Find the volume of a can with radius 3 in. and height 5 in.

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value inequality of non Tom's absolute value of X plus eight plus TN is less than 55. So before we can go ahead and start solving, we need to simplify. So we need to get the absolute value by itself. So let's start by subtracting 10. So that leaves me with non times. The absolute value of X Plus eight is less than 45. From here, we're going to divide by non. So now I have absolute value Of X. Plus eight is less than five. That's what I'm needing to go ahead and work twice. So we have the absolute value of X Plus eight is less than bath. So the first time I work it, I'm gonna have X plus eight is less than Bob. We'll subtract eight on both sides, so X is less than negative three. The second time I work it. I'm going to have X Plus Eight is greater than negative five, so we'll subtract eight on both sides. X is greater than negative 13. So now that I have my two solutions, I have X is less than negative three and I have X is greater than negative 13. We need to go ahead and decide what kind of solution this is. So if a number number line, I have negative 13, I'm gonna just do it by, um, on numbers. So let's start with X is less than negative three. It's an open circle going to the left and then we have X is greater than negative. 13. Open circle. Going to the right. I can see because both arrows air going towards each other. This is compound. So this is an and statement. So we're gonna rewrite our solution. We're going to use our lowest quantity, which is negative 13, which is less than X, which is less than negative three.

Linear Equations and Functions

Linear Equations and Inequalities

Matrices and Determinants

Quadratic Equations

Applications of Trigonometric Functions

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