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The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.
Making Models : Write an algebraic formula that models the given quantity.
15. The cost $C$ of purchasing $x$ gallons of gas at $\$ 3.50$ a gallon
Suppose gas costs $\$ 3.50$ a gallon. We make a model for the cost $C$ of buying $x$ gallons of gas by writing the formula $C=$ _________.
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an equation with a fraction in it. So let's look at the equation. 3/11 a minus one equals 7/11 a plus. Not now. Even though there's fractions, I do see that there is no simplifying to do on the left side or the right side, so we are ready to go ahead and start solving for a It's a good habit to always make sure and move your variable to the right side. I'm sorry to the left side of the equation. That way our final answer will say a equals. And then whatever the solution is, so we need to go ahead and subtract 7/11 A from both sides. Now, when adding or subtracting fractions, you have tow have a lot denominator. In this case, both fractions already have a common denominator, so we're ready to subtract. So 3/11 minus 7/11 is negative for 11th. Hey, minus one equals nine. Now let's add one to both sides so that I cancel out my ones on the left side. So I'm left with negative four 11th a equals non plus one is 10. Now that we've got a fraction, we're gonna need to go ahead and finish solving for a typically A lot of times we're left with a division right here. But this time we're actually looks like since we have a fraction, it may be something different. Well, let's look, the A and the negative 4 11 are actually being multiplied together, so we're still actually dividing. But because we're doing a fraction, we're gonna do a little different. What we're gonna do instead is we're gonna go ahead and multiply both sides by the reciprocal, which means we're gonna multiply both about negative 11/4. And I'm gonna go ahead and change my 10 toe a fraction by putting it over one. So this means that a is gonna equal negative 110 over four. Now, I can already see that I can reduce that fraction to simplest terms. And when I do, I could divide them both by two. I'm gonna have negative 55 over to
Linear Equations and Functions
Linear Equations and Inequalities
Matrices and Determinants
Applications of Trigonometric Functions