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07:20

Alix S.

Using Models Use the model given to answer the questions about the object or process being modeled. The gas mileage $M($ in milgal) of a car is modeled by $M=N / G,$ where $N$ is the number of miles driven and $G$ is the number of gallons of gas used. (a) Find the gas mileage $M$ for a car that drove 240 mi on 8 gal of gas. (b) $A$ car with a gas mileage $M=25$ mi/gal is driven 175 mi. How many gallons of gas are used?

02:07

Taylor S.

Suppose gas costs $\$ 3.50$ a gallon. We make a model for the cost $C$ of buying $x$ gallons of gas by writing the formula $C=$ _________.

06:25

Daniel P.

Using Models Use the model given to answer the questions about the object or process being modeled. The portion of a floating iceberg that is below the water sur- face is much larger than the portion above the surface. The total volume $V$ of an iceberg is modeled by $$V=9.5 S$$ where $S$ is the volume showing above the surface. (a) Find the total volume of an iceberg if the volume show- ing above the surface is 4 $\mathrm{km}^{3}$ . (b) Find the volume showing above the surface for an ice- berg with total volume 19 $\mathrm{km}^{3}$ .

02:33

Using Models Use the model given to answer the questions about the object or process being modeled. The power $P$ measured in horsepower (hp) needed to drive a certain ship at a speed of $s$ knots is modeled by $$P=0.06 s^{3}$$ (a) Find the power needed to drive the ship at 12 knots. (b) At what speed will a 7.5 -hp engine drive the ship?

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people with solving inequalities. Let's look at the problem. Negative three Monos six. Tom's four X plus six is greater than negative 111 now, just like you would with an equation. We always start with simplifying both sides. So on the left side, I noticed I have this parentheses that I want to get rid of, so we need to do distributive property, so we need to multiply everything in that parentheses by negative six. So that means I'm gonna have negative three negative. Six times four x is negative. 24 x and negative. Six times six is negative. 36 is greater than negative 111 negative three minus 36 is going to be negative. 39 Because we do want to go ahead and combine like terms minus 24. X is greater than negative 111. Let's go ahead and add and subtract anything we need to add and subtract. So we need to add 39 to both sides. And when I do, I get negative 72. So I have negative. 24 X is greater than negative 72. We're going to divide by negative 24 now because I'm dividing by negative 24. It is really critical to remember that that means that my inequality son is going to change. So I'm gonna go ahead and change it from greater than two less than so I have X is less than and negative 72 divided by negative 24 is positive.

Linear Equations and Functions

Linear Equations and Inequalities

Matrices and Determinants

Quadratic Equations

Applications of Trigonometric Functions

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