Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉Join our Discord!


Numerade Educator



Periodand Amplitudeof Trigonometry Functions - Example 2

The period of a periodic function is the time elapsed for a complete cycle. In trigonometry, the period, usually denoted by T, is the length of a circular arc in the unit circle, which is the inverse function of the sine function. The period of a periodic function is the time required for the function to repeat itself. For example, if the period of a function is 2?, then the function repeats itself after every 2? units of time. The inverse function of the sine function is the circular function, which is defined as the length of the arc of the unit circle between the point (1,0) and the point (x,y). The period of a function is a measure of the frequency of the function.


No Related Subtopics


You must be signed in to discuss.
Top Educators
Lily A.

Johns Hopkins University

Boris M.

University of North Carolina at Chapel Hill

Shubham P.

University of Washington

Heather Z.

Oregon State University

Recommended Videos

Recommended Quiz

Algebra 2

Create your own quiz or take a quiz that has been automatically generated based on what you have been learning. Expose yourself to new questions and test your abilities with different levels of difficulty.

Recommended Books

Video Transcript

amplitude and the period of why equals tangent times negative one third. So to define this, we need to find our A and R B are a In this case, even though there's not one there were gonna it's kind of like understood coefficient is going to be one and R B is negative one third now because we're talking about tangent, remember, there is not an app amplitude. So any time you're doing tangent, you will not have an amplitude for our period because we're doing tangent. That's gonna be we're gonna do radiance on this one. That's gonna be pi divided by the absolute value of B. So for this one, that would be pie divided by absolute value of negative one third, which would be pie divided by just positive one third. And in order to solve this, we're going to divide. We're gonna multiply everything about the denominator, so they'll be three that cross out on the bottle. So that means our period would be three pie because three times pi would be three pie