Findteh Minimumor Maximum Values - Example 2
Graph Quadratic Functions - Example 2
Graph Quadratic Inequalities - Example 2
Solve Quadratic Equations Algebraically - Example 2
Solve Quadratic Equationsby Factoring - Example 2
Liberty University
Dividing Complex Numbers - Example 2


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four divided by five plus three I In order to do this, we're going to the complex conjugate of our denominator. So it's gonna be we're gonna multiply this division problem by five minus three on both top and the bottom. So that would give me 20 minus 12. I over. I'm gonna have five. We're gonna use full George denominator. So five times five is 25 five times negative. Three eyes negative. 15 I three times five eyes positive. 15 odd. These two are gonna cancel out because they're the same ones. Positive ones. Negative. And three odd times Negative. Three odds. Negative. Non. I squared. So we're gonna have 25 minus not I square. So now what we're gonna have is we need to go ahead and simplify this bottom section. Um, so our top we don't have anything to simplify, so we're gonna keep 20 minus 12 I and on the bottom, we're gonna change that. I squared to negative one, so we'll have 25 minus non times. Negative one. So that's gonna be 25 plus nine. So we're gonna have 20 minus 2012 I over 34 so we can simplify this and we're gonna split it into two separate fractions. So we'll have 20 over 34 minus 12. 12/34 I and we can reduce both of these fractions. 20/34. It's gonna reduce to 10/17, minus 12/34. 6/17 I. So our solution is 10 seventeenth's minus 6. 17.

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