maximum value of the quadratic function F of X equals negative X squared plus four X plus one. So let's go ahead and let's label are A, B and C Well, are a is gonna be with her ex square. So it's negative one b is going to be positive for and see is gonna be one I noticed that my a is negative one. This means that my parabola is gonna be downward opening So that means we're going to have a maximum value and we're gonna find that by really focusing in on r B R B is four. So we're gonna use the formula where we're gonna find the X coordinate of our Vertex, which will be X equals negative B over two A. So we're gonna have negative four over two times negative one, which would be negative four over negative too. Which means that our X coordinate is going to be positive too. Now that I know that I'm gonna plug that into our formula so we could have negative two squared plus four times two plus one. So that's gonna be negative for plus eight. Plus one is going to tell me that why is going to equal five. So our maximum value is where y equals five

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maximum value of the quadratic function F of X equals negative X squared plus four X plus one. So let's go ahead and let's label are A, B and C Well, are a is gonna be with her ex square. So it's negative one b is going to be positive for and see is gonna be one I noticed that my a is negative one. This means that my parabola is gonna be downward opening So that means we're going to have a maximum value and we're gonna find that by really focusing in on r B R B is four. So we're gonna use the formula where we're gonna find the X coordinate of our Vertex, which will be X equals negative B over two A. So we're gonna have negative four over two times negative one, which would be negative four over negative too. Which means that our X coordinate is going to be positive too. Now that I know that I'm gonna plug that into our formula so we could have negative two squared plus four times two plus one. So that's gonna be negative for plus eight. Plus one is going to tell me that why is going to equal five. So our maximum value is where y equals five

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