Solve Quadratic Equations Algebraically - Example 2
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Liberty University
Graph Quadratic Inequalities - Example 2

# Algebra 2

## Topics

Quadratic Functions

## Comments

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## Video Transcript

quality wise, greater than or equal to X squared minus 10 X plus 25. So let's find a couple of points beforehand. So let's start. First of all, let's find our Y intercept and our Y intercept is going tobe a 25. So when we x zero wise 25 now, I'm not gonna graph that point on this graph because I don't my wife don't go up that high. If you have a larger graph, you could. But that kind of least gives us a starting point. Then let's find our axes of symmetry. Axes of symmetry says it's negative. Be over to a So for this one, that would be negative. Negative. 10 over two times one. So that's going to be positive. 10 over to which is going to be five. So our axes of symmetry is when X is five and we're gonna use that it's one of our points. So I'm gonna kinda go ahead and just draw some well dotted lines there, so we know that we're gonna pick points the left to the right of that. So let's go ahead and use five as one of our points. So we have why is greater than or equal to five squared? Modest 10 times fave plus 25. And if I worked that out, that's going to give me zero. So right there is 50 Alright, so let's pick some points to the left and to the right. So let's just go 12 So let's do positive four and let's do positive. Six. So wise, greater than or equal to four squared minus 10 times four plus 25 is going to give me one. And why is greater than or equal to six squared minus 10? Tom six plus 25 is also going to give May 1. So let's do a couple more points. So let's do positive three and let's do seven. That'll kind of get us on both ends. So if I put in three, so that's going to be so we put in three squared minus 10 times three plus 25 that would give us four. And then if we put seven in, that would also give us four. Now let's decide on our line and where we're shading. So this equation says that why is greater than are equal to so because this is equal to We're going to be doing a solid line so we can do pink as our solid line and we're going to draw it out, and I I need to do it a little bit lighter, but that's okay. All right, So there's are solid lawn and because the equation is greater than we're gonna be shading. And this is one of those instances that we're actually going to be shading, uh, inside the parabola. So we're gonna be shading this entire area right here. So even even if it goes a little bit above the parable, that's absolutely five just to demonstrate that these air possible solutions for this