Solving Quadratic Equationsby Completingthe Square - Example 2
The Discriminant - Example 2
Adding Subtracting And Multiplying Complex Numbers - Example 3
Complexand Imaginary Numbers - Example 3
Dividing Complex Numbers - Example 3
Liberty University
Solve Quadratic Equationsby Graphing - Example 2


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squared minus three X equals zero. We're gonna work out this quadratic equation. Now, this one, even though it's only got two terms, were good to start working this one out because that C term would actually be zero. So we can if you need to write it in, you can. You don't have to, but this quadratic equation equals zero. So we're ready to start going ahead and making our X y table Well, because the y intercept or why intercept equals zero, I can go ahead and use. That is one of my points. So that means my ex would be zero. My wild would be zero. So that actually tells me one of my solutions right there. One of my solutions is going to be zero, but we need to decide on some of the others. So let's use a couple of points around zero and a good two points good to use or one and negative one, and we'll kind of see what they do to determine what's gonna happen. Now you can go ahead and find your axis of symmetry. Remember, that's negative. Be over to a So for this instance, that would be negative negative 3/2 times one which would be three over to. So that means that my axis of symmetry would be three has which would be the same as, like, 1.5. So that means it would be somewhere almost purple dots would be my axis of symmetry. So somewhere over here is where my parabola is going to shift. So really, and truly I need to be focused mawr because this is gonna be an upward going. I need to be focusing more on those almost positive numbers. So I'm actually not going to do negative one. Let's just do one and two, because what I'm gonna see is I'm going to see it shift to the positive. What's gonna happen over here at the zeros is gonna continue going up and to the left. So let's try one. So we'll do one squared minus three times one, So that would be one minus three, which would give me negative, too. So I'd have negative. I would have negative too, right here. So let's sue. So that would be one negative, too. So I'm not yet shifted going up, but at least we can kind of see, this is we're not at that point yet. Going up. Alright, so let's do two now. So let's do two squared minus three times to. So this would be four minus six, which would be negative, too. So since this one is also negative, too, I can say that somewhere around here we know this is where it's going to shift. So around this point is where we're going to be getting that switch. So now let's do let's do three as another point. So we'll have three squared minus three times three's. That's non minus nine, which equals zero. So we'll have zero for three and I have my other. There's my other solution. So that means that my line is kind of going in this direction right here. That's not exactly could be going down a little bit more on the Vertex, but remember, we're looking for the solutions, and so right here are my two solutions, where X equals zero and X equals three. So my solutions are zero three

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