Solve Quadratic Inequalitesby Graphing - Example 3
Solve Quadratic Inequalitesby Graphing - Example 4
Adding Subtractingand Multiplying Complex Numbers
Complexand Imaginary Numbers
Dividing Complex Numbers
Liberty University
Solve Quadratic Inequalitesby Graphing - Example 2


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quadratic inequality to solve it. Um, for this one, we're gonna factor, and we can actually do just regular factoring on this one. So I'm gonna make it actually say being equation instead of it, inequality for the factoring purposes. So let's go ahead. We need to find two factors of negative 35. Then when I add together, we're going to give me negative, too. Well, those two factors, we're gonna be negative seven and positive five. Because when I add them together, they do give me negative, too. So that's X minus seven and X plus five. What equals zero. So we're gonna go ahead and solve those. So X minus seven equals zero at seven. X is going to be positive. Seven X plus five equals zero. We're gonna subtract five X would equal negative five. So we're gonna go ahead and we know that X is going to be positive. Seven in negative five. And these were Y zero. So there's my exit seven and negative five. So those are my two points for two solutions. We kind of need to get the idea of the rest of the parabola to finish finding the solution. So for this one, or why intercept? It's gonna be negative. 35. That's gonna be pretty far down. So we're not gonna have that on this graph. Ah, the axis of symmetry, though, is going to be negative. Negative. Negative, too. Over to. So that's gonna be to over two, which is one. So our axes of symmetry is going to be approximately right there. So that means that whatever I probably is doing is going to come down here and here, and it's gonna keep going up because it is a positive. Now, this did say that it was a less than zero. And if you notice that in this case, our Vertex is under the X axis, which is why it is less than zero Now, this one said it is above our great greater than or above zero. I'm sorry, but our vertex is less than so. This is one of those that's gonna be separated within. Or so this one is a case where X is going to be less than or equal to negative Five or X is greater than or equal to seven

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