Solve Quadratic Inequalitesby Graphing - Example 4
Adding Subtractingand Multiplying Complex Numbers
Complexand Imaginary Numbers
Dividing Complex Numbers
Findthe Minimumand Maximum Values
Liberty University
Solve Quadratic Inequalitesby Graphing - Example 3


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inequality in order to solve it. Now, in order to do this one, we're gonna have to use the quadratic formula, which has X equals negative B plus or minus the square root of B squared minus four A c over to a. So, for this one, we're gonna use X equals negative five plus or minus the square root of five squared minus four times, two times negative, six over two times two. Well, if I simplify that, I have negative five plus or minus the square root of 25 plus 48 over four, which will reduce to negative five plus or minus the square root of 73 over four. Now, 73 is a complex number. It's not a perfect square, So that means that X is going to equal negative five, plus the square root of 73 over four, which is approximately 0.9 and X is going to equal negative five minus the square root of 73/4, which is approximately negative, 3.4. So those are two solutions we're gonna use, so we're gonna have X is 0.9 and negative 3.4, so well, kind of round those zero point. Now that's pretty close. Toe one and negative 3.4 is gonna be about in between. So there's are two points. This is a positive. So it is going to be going upwards opening upward. Our Y intercept is gonna be negative. Six. So it'll be right there. Or axes of symmetry is going to be negative. Five over two times two, which would be negative. 5/4. So that's gonna be a little bit of above the one not quite 1.5, but just to kind of give you an idea on that one, So this one's going to kind of come down and then come back up, so that would be kind of similar to what it would look like. Now, this one does say it is less than zero, and my vertex is below the X axis, which means that we're gonna have this is connected with an and so it's negative. 3.4 is less than X, which is less than zero point. Not

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