Adding Subtractingand Multiplying Complex Numbers
Complexand Imaginary Numbers
Dividing Complex Numbers
Findthe Minimumand Maximum Values
Graph Quadratic Functions
Liberty University
Solve Quadratic Inequalitesby Graphing - Example 4


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by, um, in solving at the same time. So for this one, we're going to use the quadratic formula. Quadratic formula says that negative B plus or minus the square root of B squared minus four. A. C divided by two A. Will give me our X value. So for this one, we're gonna have negative negative 10 plus or minus the square root of negative 10 squared minus four times five times one over two terms far. So we'll have simplify that to tiene plus or minus the square root of 100. Modest 20 over TN would be a 10 plus or minus the square root of 80 over 10. So 80 is complex numbers, so we're just gonna kinda type these in, and I'm gonna give you about what they are. So we have 10 plus, The square root of 80 over 10 is going to be approximately 1.9 and 10 minus the square root of 80 over 10. It's gonna be approximately zero 0.1, so we'll have X is 1.9. Sorry, x. It's 1.9 x is 0.1. So these are gonna be pretty close. This one's gonna be about to. This one's gonna be a little closer to the zero. Let's come and find a few more points or why Intercept is going to be one. So this one's OK, So this is gonna be a pretty close, and our axes of symmetry would be negative. Negative tin over two times five. So that would be 10/10, which would be one. So that right there would be our axes of symmetry. So basically, what's gonna happen is our lines going to come down and it's going to come back up at the axis of symmetry. All right, so let's look at this. This said that this is less than zero, and our Vertex does fall below the exact So this means we're combining with. And so our answer would be 0.1 is less than X, which is less than 1.9

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