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Missouri State University
Harvey Mudd College
The model $L=4 S$ gives the total number of legs that $S$ sheep have. Using this model, we find that 12 sheep have $L=$ __________ legs.
Using Models Use the model given to answer the questions about the object or process being modeled.
The gas mileage $M($ in milgal) of a car is modeled by $M=N / G,$ where $N$ is the number of miles driven and $G$ is the number of gallons of gas used.
(a) Find the gas mileage $M$ for a car that drove 240 mi on 8 gal of gas.
(b) $A$ car with a gas mileage $M=25$ mi/gal is driven 175 mi. How many gallons of gas are used?
$3-12=$ Using Models Use the model given to answer the questions about the object or process being modeled.
The sales tax $T$ in a certain county is modeled by the formula $T=0.06 x .$ Find the sales tax on an item whose price is $\$ 120 .$
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So in this example, we're going to use a different way that might help you give you a visualization as to how to find the some indifference for rational numbers. So one thing you can do is use the number line to find each summer difference. So that's what I'll show you an example of here. So for part A, we have negative three plus e. So whenever you're going to use a number line, you always want to make sure your problem is Aaron, as in addition problem, which in this case it already is. So now we're going to set up our number line. So I'm gonna put 20 here in the middle, negative one negative to negative three and then I'll go all the way up to positive 8345 Actually, I'll just go to six. That should be plenty. All right, so we're always gonna start our number line with the first number Negative three. So that would be right here. So here's our starting point, and we're adding a positive eight. So because our second number is positive, that tells us we're going to go to the right eight units. So we go to the right. Eight units. We're gonna go. 12345678 So, as you know this, we end up at positive five, which tells us that negative three plus eight is positive. Five. All right, so let's try part B. We have negative for minus two. Again. We first have to write this as an addition problem. So we're gonna bring down our first number, Negative four. And we're gonna add the office of the positive two, which is negative. Two. All right, So let's go here and set up our number line again. I'll start with zero in the middle. I'll go. 123 I'll never started. Go. Negative. One negative to negative three. Negative four. Negative five. Uh, well, stick a negative six. And at the end there. All right. So again, we always start at our first number, which in this case, is negative. Four. But we're adding negative to so because we're adding a negative number that tells us we're going to go to the left. So we're gonna start hearing negative for, and then we're gonna go back 12 which is going to leave us here at negative six. Which tells us that negative four minus two is negative. Six. So, again, when the second numbers positive, you move to the right. When the second number is negative, you move to the left. All right, so let's start try our last example. We have negative one minus negative three. So again, the first thing we need to dio is change it into In addition, problem. So we'll bring down our first number, negative one. And then we're gonna add the office it of negative three, which is positive. Three. So now that's in addition. Problem. We can set up our number line. I'll started zero. I'll put 123 Negative one negative to negative three. All right, so on our number line, we're going to start with our first number, negative one. And because we're adding a positive three, remember? That's gonna tell us to go to the right. So we're gonna go 123 to the right, and we end up with positive too. So that means that negative one minus negative three is positive too.
Solve Linear Inequalities
Systems of Equations and Inequalities
Graph Linear Functions