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Baylor University

University of Michigan - Ann Arbor

02:13

Taylor S.

Using Models Use the model given to answer the questions about the object or process being modeled. A mountain climber models the temperature $T$ ( in $^{\circ} \mathrm{F}$ ) at elevation $h$ (in ft) by $$T=70-0.003 h$$ (a) Find the temperature $T$ at an elevation of 1500 $\mathrm{ft}$ . (b) If the temperature is 64$^{\circ} \mathrm{F}$, what is the elevation?

07:20

Alix S.

Using Models Use the model given to answer the questions about the object or process being modeled. The gas mileage $M($ in milgal) of a car is modeled by $M=N / G,$ where $N$ is the number of miles driven and $G$ is the number of gallons of gas used. (a) Find the gas mileage $M$ for a car that drove 240 mi on 8 gal of gas. (b) $A$ car with a gas mileage $M=25$ mi/gal is driven 175 mi. How many gallons of gas are used?

01:56

Suppose gas costs $\$ 3.50$ a gallon. We make a model for the cost $C$ of buying $x$ gallons of gas by writing the formula $C=$ _________.

0:00

Kyle I.

Using Models Use the model given to answer the questions about the object or process being modeled. The distance $d$ (in mi) driven by a car traveling at a speed of $v$ miles per hour for $t$ hours is given by $$d=v t$$ If the car is driven at 70 milh for 3.5 $\mathrm{h}$ , how far has it traveled?

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we're being asked to evaluate the following expressions. So remember the word evaluate means to find the value of So I'll start with part A. We have to raise to the floor power. Well, in this case are basis to our exponents four, which means to multiply two by itself four times. So we can rewrite this as to times two times, two times two. And now we can multiply in order from left to right. Well, first we'd have two times two, which is four. And then we'll bring down the remaining choose. Next we would multiply four times to which is eight. We'll bring down that last two and eight times two is 16. So what we found is to to the fourth is equal to 16. Now, for part B, we have negative three being raised to the third power. So in this case, our bases negative three and our exponents is positive three, which means we need to multiply negative three by itself three times. So we can rewrite this as negative three times negative three times negative three and now again will multiply in order from left to right. Well, negative. Three times negative. Three is positive. Nine. And then we'll bring down that last negative three. And then we'll have nine times Negative three, which is equal to negative. 27. So negative three raised to the third Power is negative. 27. Okay, lastly, we have C nine to the second power. Or remember Weaken River. We can read that as nice where? Well, our bases nine and our exponents is, too. Which means we need to multiply nine by itself two times. So we'll do nine times nine. Well, nine times nine is 81. So now we found that nine squared is equal to 81.

Linear Functions

Solve Linear Inequalities

Functions

Systems of Equations and Inequalities

Graph Linear Functions

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