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Idaho State University
01:04
Taylor S.
Using Models Use the model given to answer the questions about the object or process being modeled. Mintonville School District residents pay a wage tax $T$ that is modeled by the formula $T=0.005 x .$ Find the wage tax paid by a resident who earns $\$ 62,000$ per year.
01:38
Jinseop S.
$3-12=$ Using Models Use the model given to answer the questions about the object or process being modeled. The sales tax $T$ in a certain county is modeled by the formula $T=0.06 x .$ Find the sales tax on an item whose price is $\$ 120 .$
01:56
Suppose gas costs $\$ 3.50$ a gallon. We make a model for the cost $C$ of buying $x$ gallons of gas by writing the formula $C=$ _________.
0:00
Kyle I.
Using Models Use the model given to answer the questions about the object or process being modeled. The distance $d$ (in mi) driven by a car traveling at a speed of $v$ miles per hour for $t$ hours is given by $$d=v t$$ If the car is driven at 70 milh for 3.5 $\mathrm{h}$ , how far has it traveled?
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we're being asked to evaluate each expression if X is equal to negative two. So if you look at the the problems for A and B, they look very similar, except in part A. We have a prime facie around three X and in part we we don't. So what we're gonna see is does that parentheses actually mean something. So let's go ahead and find part A. So the first thing we need to do is substitute negative to in place of X. So and remember, three is getting multiplied by X. So when we do this, we're going to have the quantity of three times negative too. And this is all getting raised to the second power. Now, the first thing we need to do is before we raise it to the second power, we need to multiply those two values inside that out of prophecy. Well, three times negative two is equal to negative six. So we're now gonna have the quantity of negative six being squared. Well, remember, the square of value means to multiply it by itself twice in this case, so we need to multiply negative six by negative six. Well, negative. Six times negative. Six is positive. 36. So if sound that the answer, The part a is positive 36. Now let's go The part b Very similarly. The first thing we need to dio is substitute negative to in place of X. So when we do this, we're gonna bring down the three in place of X. We're gonna put negative two and negative two is getting square. So now take a look at your problem. The first thing we're going to need to dio is determined. What? Negative to square this. So we're gonna bring down our initial three, and we're gonna multiply that by the value of negative two squared. Well, how do we find negative two squared? Well, that means to multiply it by itself twice. So we need to do negative two times. Negative too. So, as we mentioned before, now we actually have to go ahead and multiplied the two negative twos. Well, negative. Two times negative two is positive. Four. So we're gonna bring down the three, and it's getting now multiplied by positive four. Well, three times four is equal to 12. So the answer the part B is 12. So as you can see those parentheses make a big difference because in part A, we had the first multiply three times negative to before. Squaring it as opposed to impart be where there was no Prem facie. We needed to square the value for X, which in this case was negative. Two. Then multiply the result by three. So make sure you're very careful. Ble careful. Excuse me about whether you multiply first or square first. So all depends on whether there's a set of parentheses in your problem.
Linear Functions
Solve Linear Inequalities
Functions
Systems of Equations and Inequalities
Graph Linear Functions
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