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Campbell University

Oregon State University

University of Michigan - Ann Arbor

07:29

James C.

Using Models Use the model given to answer the questions about the object or process being modeled. An ocean diver models the pressure $P$ ( in $\mathrm{lb} / \mathrm{in}^{2} )$ ) at depth $d$ (in ft) by $$P=14.7+0.45 d$$ (a) Make a table that gives the pressure for each 10 -ft change in depth, from a depth of 0 ft to 60 $\mathrm{ft}$ . (b) If the pressure is $30 \mathrm{lb} / \mathrm{in}^{2},$ what is the depth?

00:26

Kelli P.

Making Models : Write an algebraic formula that models the given quantity. 15. The cost $C$ of purchasing $x$ gallons of gas at $\$ 3.50$ a gallon

0:00

Kyle I.

Using Models Use the model given to answer the questions about the object or process being modeled. The distance $d$ (in mi) driven by a car traveling at a speed of $v$ miles per hour for $t$ hours is given by $$d=v t$$ If the car is driven at 70 milh for 3.5 $\mathrm{h}$ , how far has it traveled?

02:33

Taylor S.

Using Models Use the model given to answer the questions about the object or process being modeled. The power $P$ measured in horsepower (hp) needed to drive a certain ship at a speed of $s$ knots is modeled by $$P=0.06 s^{3}$$ (a) Find the power needed to drive the ship at 12 knots. (b) At what speed will a 7.5 -hp engine drive the ship?

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for being asked to evaluate, to given expression, using the order of operations and to help us. I wrote our order of operations. Step over here, Off to the right. So let's go through each step. So Step one grouping symbols. Well, I see we have a bracket here, so we have to evaluate the order of operations within this outer bracket. So inside the bracket, we have two operations. We have subtraction, and we have multiplication. So according to order of operations, we should take care of our multiplication first. Well, three times two is equal to six, so we're going to rewrite our expression, so we're gonna have 15 minus. We're gonna bring down the to we're gonna have our bracket. We're gonna have eight minus on. Like we said, three times two is equal to six, and then we'll close our bracket. Well, we still have our grouping symbol, But inside our group in simple, we only have eight minus six. So let's evaluate. Well, eight minus six is equal to two. So Ram 15 minus two, then bracket, too. So now we've taken care of our grouping simple, and it's okay to just be left with one number inside. Because remember that negative or the two on the outside touching that bracket means multiplication. Now, Step two is exponents. But we don't have any exponents, so we could skip that next, Multiply and divide from left to right. What? We do have multiplication. We have two times two, which is equal to four. So I have 15 minus four and now we only have one operation left. We have 15 minus four, which is equal to 11. So what we've found is the value of our expression is equal to 11.

Linear Functions

Solve Linear Inequalities

Functions

Systems of Equations and Inequalities

Graph Linear Functions

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