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00:33

Dungarsinh P.

If $f(x)=x+\sqrt{2-x}$ and $g(u)=u+\sqrt{2-u},$ is it true that $f=g ?$

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Amy J.

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Kim H.

Virendrasingh D.

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All right. So we want to find the critical points of dysfunction and recall that the critical points of a function of two variables are the points X y, where the Grady int is equal to zero. Or in other words, well, this is a vector equaling zero. And now here I really mean like, the zero vector. So this happens exactly when the partial, with respect to X zero and the partial with respect to why is equal to zero. Okay, so what is the partial with respect to X? Well, it's gonna be two x e to the X squared plus y squared in the nef y is to why need to the X squared plus y squared? Okay, So if I said these equal to zero, what is the only way that both of these were going to be zero simultaneously? Well, this exponential is always positive. So the only way this is going to be 00 and the only way this is going to be zero is if y zero so the Onley critical point is going to be the origin 00

Multiple Integrals

Vector Calculus

06:52

09:20

06:47

07:55

04:57

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04:59

08:13