Texas Tech University
The Integrated Rate Laws - Example 1


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Now let's solve an example. So in this example, very dealing with s 02 C l to gas that is the composing, too eso to gas and C l to gas. Now they're telling us in the question this reaction is first order. And they're also telling us that the K constant is equal to 3.8 times 10 to the power of negative four. And the initial concentration, which is eso to sell to zoo equals two 0.3 Mueller. And they're asking us what would be the concentration off s 02 c l two at the time seven 96 seconds. So, basically, you just need to write the knowns. Once you're reading to question, they can tell you a story. You don't need to get lost in the story. All you need to do is to find the K if they give it or if they ask it, find the initial concentration, if they ask it, or if they do it just right down the, uh, final concentration and the time if they give in our case, it is going to be 7926 seconds. So just write all these down and then go with your integrated read law. Uh, equation. Let's remember it together one more time. What? That was Ellen. 80 equals two minus Casey plus Ellen zero now or here are 80 is going to be this guy. So they're asking us to find this inside inside the Ln equation equals two minus K. 3.8 times tend to the poor of negative. Four times are t is 7 96 plus Ellen are a zero is 0.3 now. We want sold this equation. So basically, what we want to do is you want to multiply this term and add the l N zero point tree inside here. And once we do that, we are going to raise both sides to the power off e. So why are we going to do that? You want to do that simply because you want to get rid off this Ellen term? You just want the inside the brackets. And if you remember e to the power off Ln s 02 c l two would give us. And so too C l two. Whatever we have inside this Ln equation, we would get it out if he raised it to the power off e. So once we do this math, what we're going to end up with is going to be zero point to to to

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