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Carleton College

University of Central Florida

Rice University

03:15

Keenan M.

What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm? 200 pm?

03:16

Kevin C.

If two objects, A and B, of different temperature come into direct contact, what is the relationship between the heat lost by one object and the heat gained by the other? What is the relationship between the temperature changes of the two objects? (Assume that the two objects do not lose any heat to anything else.)

02:46

What is kinetic energy? What is potential energy? List some examples of each.

01:48

What is electronegativity? What are the periodic trends in electronegativity?

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And so if the first problem, we will be determining the density of an atomic solid that has a BCC structure with an atomic Mueller Mass. 30.2 g promote and an atomic radius of 285 centimeters. And so today this problem. We need to recall that for destiny, we need to figure out the mass and divided by the volume. And so, for the vast, we need to figure out the number of atoms in a unit self, which we can then convert using of God rose number on, then convert again using the more mass to get the mass immigrants. And we'll also need to find the volume of one unit cell. And so, using the fact that we have the atomic radius, we can figure out the length. And so if we have the edge light cube, we have the volume, and we'll also be doing this in units outside meters. Cute. And so let's recall that for a BCC structure, if you have hey, simple Cube. This is essentially the simple cubic plus one Adam in the center. And so what's your call that in this case, we have Adams on each corner of the unit Self show here, and we also have one right in the side. And so what? We're calculating the number of atoms we need to make sure that we are only counting the volume that is inside the unit self, because we know that in three dimensional space there are unit cells packed everywhere. And so again, we need Thio only account for the volume inside the unit itself rather than the whole Adam. And so we know that for each of the corners, each sphere or in this case, Adam contributes a volume of 18 and we have eight of these corner autumns, and so this would give us a total of one Adam. And we also know that we have one atom right in the center, and so that contributes to a volume one. And because we have one Adam, this would simply be one. And so the total number of atoms for the CSL could be to Adams. And so we use this information to calculate the mask since we have our feels that we need. But we also need to figure out the edge length. And so let's say that the edge length for this you insult is a and so we actually need to figure this out based on the atomic radius. And so we know that the direction where we have the close backpacking So basically the length where we have all of the radio of the atom touching each other is actually through the body diagonal. And so if we draw this out, we actually have three of these atoms touching each other on DSO. We can draw this and so we actually do not know this length. But we know that this length is far and so we can bear out a relationship between four are and a so that we can figure out a and surface part. We actually need to find information for two different triangles and so we can use this triangle to figure out the relationship between four and a. But we also need to figure out what this like this because we know that this is a But this is unknown. So we can also do a different triangle to calculate that like as well. And so for the green triangle, we see that we have a length of a on one side and on the other side. And so this is a special triangle. And so this is simply Joseph route to A And using this information, we can now figure out the dimensions for the Red Triangle which will again give us information about our relation today. And so we know that miss like this a and this one is roots of any from be drawing. Although we did before and we know that this is for our and so we can use Pythagorean is there to actually calculate this out so we can again make this relationship. And so we know that a squared plus we're to a squared is equal to four r squared And so we have a squared plus to a squared is equal to 16 r squared and we also have that three a square is 16 r squared and so we can divide both sides by three and then we can square it both sides And so we end up with a is equal to four far over three And so now we can use this relationship too far away is by Palladian art Since we know that it is 285 computers. And so if we do, this is equal to floor over route three times 285 5 commuters. And so if you put this into our calculator, we get 658.18 centimeters. And now that we have the units selling, we can now figure out the density. Since everything else is no and send, the density is equal to the mass. And so we know that we have to atoms for you. It so and so we can divide us by our cadres number. So this would be 6.22 times 10 23rd Adams. And so this is simply just us using individual analysis. And we know that's mass ISS 30.2 g per mole. And so, as a sole check will make sure that the units can slot and so the atoms can slot. I am always cancel out and you're left with Gramps, which is looking great. And we also know that we need the volume. And so this is simply the life of the unit self queued. And so we have 658.85 commuters cube, and we would also like this in terms of Centimeters Cube. And so we know that there is one times 10 from the intense centimeters for one pilot meter. And so if you do this, our point communities canceled and we're allowed to with centimeters keep. And so if you put this into our calculator, we get a final answer of 0.352 grants for a Centimeters cube. And so again, based on the information that we're given, we can calculate the density because we know the number of atoms in the unit sub, which we can then convert into math. And we also can figure out the dimensions of the unit cell given the atomic radius and understanding how the packing structure works.

Solutions

Kinetics

Chemical Equilibrium

Acids and Bases

08:50

05:39

10:01