Refer a friend and earn $50 when they subscribe to an annual planRefer Now
No Related Subtopics
Rutgers, The State University of New Jersey
University of Winnipeg
(I) A 110-kg tackler moving at 2.5 ms meets head-on (and holds on to) an 82-kg halfback moving at 5.0 m/s. What will be their mutual speed immediately after the collision?
(II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?
(I) A 7150-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s. A 3350-kg load, initially at rest, is dropped onto the car. What will be the car's new speed?
Create your own quiz or take a quiz that has been automatically generated based on what you have been learning. Expose yourself to new questions and test your abilities with different levels of difficulty.
Create your own quiz
welcome to our first example video looking at kinetic energy. So if we're going to start first by considering how much kinetic energy doesn't object have, let's say that an object has a velocity equal to 5 m per second squared has a mass equal to 2 kg thin. Aiken simply plug in and say, Well, the amount of kinetic energy it has is equal to one half m B squared. So that's one half 2 kg, 5 m per second squared squared. So we have 25 times, two times one half ends up being 25 jewels. I should note that many books instead of using Katie, will simply use K thio. Define kinetic energy or to name kinetic energy. Okay, so simple calculation here. What if we said that we wanted to know the amount of work done on an object? Uh, based on a change in kinetic energy? So we say we have a work and it's equal to We'll say our object started at rest. That means it finished with one half m. The final squared minus one half m. The initial squared will say that the final was equal to 5 m per second squared the initial equals 1 m per second squared. If we do that, then we know that this first one is 25 jewels. Because we just calculated it. Minus one half times 2 kg. I was 1 m per second squared. So one, so 25 minus one. The work done is 24 jewels to take it from V not to the final. So, um, we're able to do this work without much effort here, and in fact, it zits that easy. Um, and you may ask, what can work do then, once we know how it work, What is it useful for? Well, I'll show you in the next exam.
Equilibrium and Elasticity
Moment, Impulse, and Collisions
Rotation of Rigid Bodies