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0:00

Aditya P.

(I) A 7150-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s. A 3350-kg load, initially at rest, is dropped onto the car. What will be the car's new speed?

00:39

Averell H.

I) How much tension must a rope withstand if it is used to accelerate a 1210-kg car horizontally along a frictionless surface at 1.20 m/s$^2$ ?

03:38

Keshav S.

(II) A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 $g$'s. Calculate the force on a 65-kg person accelerating at this rate.What distance is traveled if brought to rest at this rate from 95 km/h?

04:15

Kathleen T.

(II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

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welcome to our third example video. Considering the microscopic and macroscopic picture of the kinetic theory of in this video, we're going to continue with our one leader box of 25 degrees Celsius air at one ATM and we're gonna ask ourselves what is the average energy of a particle in this box? Remember that average energy can be written as three half times K B t. And we can then find the average is equal to three half times 1.38 times 10 to the negative. 23 jewels per kelvin multiplied. Bye. The Calvin is 298. Thank you. Okay. And that's all it takes. We have our calculation of the average energy of a particle. Now you can see here that is going to be very, very small because it's the sum of all of these energies that's going to add up to our thermal or internal energy. We're going to talk a lot more about that in the next section here

The Second Law of Thermodynamics

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