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welcome to our first example video. Looking at specific heats and Kalorama trees. In this video, we're going to compare two different liquids that is water and mercury, and we're going to add some heat to each of these and see what the resulting change in temperature would be now for water. The specific heat see is going to be equal to 4190 Jules per kilogram. Calvin. And for Mercury, the specific heat is going to be equal to 140 Jules per kilogram. Kelvin. So what does this mean? Well, remember that Q is equal to M C Delta T. Let's assume that each object, we have the same amount of each and we're going to have the same initial temperature. So how will the final temperatures compare so comparing looking at this and expanding TF out, we have Q times. M of the H 20 is gonna be the same as the Mass. The Mercury Times CS. We'll just call this CS one for water times T f minus t not so TF on this side, then is going to be equal to T F is equal to que divided by M CS one plus t not and on the other side Because math will work the same. We'll have tea. Final is going to be equal to queue over em. CS two plus Tina now taking the difference between the two calling this number one and this number two What we're going to find is that t F one minus T f two is going to be equal to queue over em multiplied by one over CS one minus one over See s to. So looking at this, we know that CS one is very large and C s two is very small, which means this is going to end up being a negative number, which means that the final temperature for the mercury will be larger than the final temperature for the water. Now, this isn't particularly surprising. What it means then, is that it takes less energy to increase the temperature of mercury than it does to increase the temperature of water. And you can see that just by looking at the values here here, it will take 4190 jewels to raise 1 kg of water. One Calvin Over here we see it will take 140 Jules one, uh, to raise 1 kg of mercury up. One kelvin

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