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03:04

Kai C.

(I) A 7150-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s. A 3350-kg load, initially at rest, is dropped onto the car. What will be the car's new speed?

0:00

Muhammed S.

00:39

Averell H.

I) How much tension must a rope withstand if it is used to accelerate a 1210-kg car horizontally along a frictionless surface at 1.20 m/s$^2$ ?

04:27

(I) A 110-kg tackler moving at 2.5 ms meets head-on (and holds on to) an 82-kg halfback moving at 5.0 m/s. What will be their mutual speed immediately after the collision?

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welcome to our third example video looking at RLC circuits in this video, we're going to continue looking at the same circuit from last time and with the same frequency. And we're going to add in that we know that the initial, or at least the maximum e m f that can be supplied to this circuit is equal to 30 volts. Given these numbers, we want to find out what is the maximum current that we can have through this circuit. And then also we would like to find out our phase angle. Remember, phase angle is what we defined. That tangent of five is equal to excel minus X E divided by r and it came from analyzing the phaser diagram off this circuit when I saw this. I'll have five is equal to the inverse tangent of X l minus X c over our notice here that if we had the resonant frequency where X L equals XY, we'd have zero on the top here and we'd have inverse tangent of zero. On the other hand, if we had a circuit with no resistor in it, we'd have a number over zero situation going on here. So What would that mean? Well, uh, one over a number over zero in this case would be infinity and inverse. Tangent of infinity is simply pi over two. So we would still be able to find our fi in that case and continue with this analysis. Meanwhile, for IMAX, we can write that out as being the over Z where Z is the impedance that we found last time. The square root of r squared plus x l minus X c quantity squared so we can go ahead and plug that in and you will be able to find your current and your fi.

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