Refer a friend and earn $50 when they subscribe to an annual planRefer Now

Like

Report

No Related Subtopics

Rutgers, The State University of New Jersey

University of Washington

University of Sheffield

McMaster University

04:39

Muhammed S.

(I) A 7150-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s. A 3350-kg load, initially at rest, is dropped onto the car. What will be the car's new speed?

01:40

Keshav S.

(II) According to a simplified model of a mammalian heart, at each pulse approximately 20 $g$ of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle?

00:39

Averell H.

I) How much tension must a rope withstand if it is used to accelerate a 1210-kg car horizontally along a frictionless surface at 1.20 m/s$^2$ ?

03:09

Aditya P.

Create your own quiz or take a quiz that has been automatically generated based on what you have been learning. Expose yourself to new questions and test your abilities with different levels of difficulty.

Create your own quiz

welcome to our second example video, looking at simple circuits and alternating current in this video will consider a simple capacitive circuit with a capacitor that has a size equal to 100 micro ferrets. And we'll say that we have a frequency equal to 1000 hertz and we have a maximum applied voltage here that will be our V C, which is equal to three volts. And from this we want to find what is our capacitive reactant. Remember, capacitive react INTs is written as one over Omega time. See, So it will be one over. Remember, f is equal wages equal to two pi times f. So we have two pi times 1000 hurts multiplied by 100 times 10 to the negative six fair EDS. We have our capacitive reactions and more than that, now that we have the capacity of reactions, we can also find out what is the maximum current in this system going to be because we know that the maximum current is going to be equal to the maximum applied voltage three volts divided by the capacity of reactions. So given this, we have three volts divided by capacitive reactions which you can calculate here, and it will tell you what you need in order to write out your current as a function of time. Remember that for capacity we have cosine of omega T plus pi over two. Okay? And so that all it takes in order to find the person equations. Of course, we'll have the same voltages function of time as we have had with the maximum voltage multiplied by cosign of omega teeth.

Electromagnetic Waves

02:07

02:48

10:23

03:28

01:50

01:51

03:03

07:02

02:27

02:33

02:56

02:08