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J H.

In Exercises 7-12, match the quadratic function with its graph. [The graphs are labeled (a), (b), (c), (d), (e), and (f).] $ f(x) = 4 - (x - 2)^2 $

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In Exercises 7-12, match the quadratic function with its graph. [The graphs are labeled (a), (b), (c), (d), (e), and (f).] $ f(x) = (x - 2)^2 $

01:57

In Exercises 7-12, match the quadratic function with its graph. [The graphs are labeled (a), (b), (c), (d), (e), and (f).] $ f(x) = (x + 4)^2 $

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In Exercises 17-34, sketch the graph of the quadratic function without using a graphing utility. Identify the vertex, axis of symmetry, and x-intercept(s). $ f(x) = x^2 + 7 $

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Okay, so this is gonna be the fourth example out of our matrix equation Siri's and we've got to be minus one by four Matrix of negative four negative eight negative nine and zero is equal to a different one by four matrix of to 14, 7 and 16. So because we're just subtracting what matrices as well. So the things going on in the left side we've got subtracting matrices as as well as multiplying by a code vision. So for both of these things that we we know that we could basically just use the same rules of algebra when we're looking to isolate R B value. So the first thing I'm going to do is the opposite operation of this right here. Subtracting that matrix, which is to add that matrix. So I'm gonna add the matrix negative for negative eight negative 90 to both sides of the equation. So once we do that, we get to be is equal to 2, 14, 7 16 plus negative four and negative eight negative. Nine in zero. So at that point, we know we just have to combine it so that each position states consistent, so it's gonna be, too. What's negative? Four. Which is night of two negative 14 plus negative eight, which is six and then seven. Plus negative nine, which is negative. Two, then 16 plus zero, which is just 16. So now we've got that to be is equal to negative 26 92 16. So from here we can multiply both sides of the equation by one half because that's what's going to get rid of the two. And now our B is by itself. And then if we do one half times that matrix, well, that's just multiplying the Matrix by a coefficient, which means that we just have to make sure that it gets distributed to all four terms of that matrix. If we do that negative two times one half is negative. 16 times. One half is three negative. Two times one half is negative. One and then 16 times. One half is eight. So this right here, this B is gonna be our resulting matrix

Introduction to Conic Sections

Discrete Maths

Introduction to Combinatorics and Probability

Introduction to Sequences and Series

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