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Particle Equilibrium and Forces in Mechanics

Particle equilibrium Tension : K Spring: F = - Kox angles : da cos" TFT F= F (cosai+ cospj + easy k) Magnitude: F+ F}+F2 Rod Force: Pull A.R . GRong iguales Push BA : (2) 484 7 T/Le CA : (8) LA ; 6-78 3 3 -2 0 T = 0.6733 . LAR= 0-513316 Tc = a 0333-4c=221 DA : (?) LAB : 7 -2 -1 3 0 Tp = 0.06 . 40 = 0.42 Lb -6 -6 -6 -1 TB + Tc+ TO+ F=0 Max: 4 =9741 Lb = 04m LCD: 00-5+062 = 0.78 m ?Fx: -0.6 LAC FAC + 0.5 m LBA: No.5'+04' = 0.64 m SFy: O.S + FAC LAC + - W = 0 W= 40-9.81=392.4 N FAR > 313.92 FAB LAB PAL CAC 40 kg -0.6 0-4 0 FAC= 244.86 N 1200 244.80 = 0.20405m = 470.88 392-4 0.5 0.5 40 FAR: = 301-38 N 801.36 0.2 009/1 1200 Now we find a vector R = [%] => RX F2=11 500 300 800 X 800y = MIX =1648-98 ixjak jaksi kki oj 4 k Moment forces -> Moment force is perpendicular to the plane and direction -> Cross Product: Â x B = W. A. A. A. A. Magnitude : [] =\\/B] sine of force B & XBXB, 18, -> 3D Cross Product: ijk Rx Ry Rz = i. (RyFa-Ra Fy) -j.(RxF8-RaFx) + K· (RxT2-RxFx) Fx Fy F2 Parallel forces: If all forces on a plane are parallel to each other. M = thFing ERP - Fd - Raly - 2, Fo the Mo total is always perpendicular to FR Total. -> Counter- clock wise = + Clock wise = - Ky Wrench Example: [500] 300 600 Pick a reference point with no moment, for example A IF21= 989.95 The = 12 989.95 Mg: [4800] Mc: = (iR·?) 1851-02 9:30-41 2481-63 1551.02 930-61 2481-63 -930-61 ?=(?)? IFR12 7 M1 = 12 - 13= [181-63 Now we find a vector R = [ {] => RX F2 = 11 Y=2-061 X=1.163 RxF =M1 =1-1,-1-4. F .A.C} 500 goby = MIX =1648-9 xx0 X 300 800 = Mly = - 930. 800x-50Y = MIz : - 611-63 = 800x y. M ... CE Shot force & Arm force A Kinetics = - 800X y=2.06| x=1-163 RXF=M2=M-M=M-1 ==- CF = MLy = - 930.61 300x-500Y = MIZ 2 -68/.63 y - M .- CF F. For the rigid body equilibrium : force exist in the direction where it resist force come from certain direction. Projection of vector on amother A on B : A . O. d BR +BytBE Amount of A that's perpendicular to vector B: *= My - CF Fa V2= " + zas Relative motion 1 5810 - FBIA + PA/O B S take reference point 00 Basically V= u+ at UBIO = UBIA + VANO vectors AuBxtAyBytAule S= wt + 1 at2 6 @% = GB/0 + 420 For ladders ???????,???,?????. À - LA - Og ) Og : (AnBrtAy Bythole dbx +By'+Be