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Projectile Motion and Circular Path Problems

PROBLEM 12-97 (page 53, 14th edition) PROBLEM 12-101 (page 50, 13th edition) PROBLEM 12-110 (page 52, 12th edition) The skier leaves the ramp A at angle 04 = 25° with the horizontal and hits the ground at B. · Determine the initial speed va and the time of flight. 0A VA A 4 m 5 3 4 100 m B PROB12_110.jpg Copyright 2010 Pearson Prentice Hall, Inc. 12-97 (page 53, 14th edition) 12-101 (page 50, 13th edition) 12-110 (page 54, 12th edition) COMPLETION OF PROBLEM · Trajectory equation y(x) = a(x ! x, )2 + b(x ! x0)+ yo a = ! 2vo cos- "0 g 2 " b = tano · Data 00 = 25! (x0, yo)=(0, 4)m (x, y)=(80,! 66)m : !60= ! 9.81(80)2 + 80 tan 25° + 4 2vo cos2 25° Solver Vo = 19.4m/ss · Projectile equation for horizontal motion x(t) = X0 + Voxt 80 = (19.4 cos 25°)t Solve: t = 4.54s PROBLEM 12-130 (page 63, 13th edition) The motorcycle travels along the 300 ft radius vertical circular path. Its speed at A is 2 ft/s and increases by (s/25)ft/s2 where s is the distance along the path from A in feet. Determine the motorcycle's speed, acceleration and travel time at B. Determine the motorcycle's travel distance, speed and acceleration 15 seconds from A. 300 ft 60° A 300 ft 1 B Figure: 12_P129-130 Copyright 02013 Pearson Education, publishing as Prentice Hal