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Analysis of Forces and Moments in Mechanics

1. Z Mz 3 < Mx Bx B x A By 500 My TCA 5 b) Coordinates: A = (3,0,0) B = (0, 0,0) C = (0, 5,-1) D = (0,5,0) From C, TCA = TCA TEA rca . (31-5j +k) x From D , ?= 3001 - 500k From B. B = 82 i + By j EF2 : 3x + 300 + Bx = 0 EFy: - 5X +By = D EF2: X - 500 = 0 300 y C From moments about B, E (MB) = Mxi + Myj + M2k ij k i j k E'(MO) = M + 0 5 300 0 -500 + 3 0 0 3X -5x x = 1 (-2500) + K (-1500) - j (3x) + k(-15x) EMx: Mx -2500=0 E' My : - 3x + My = 0 EM2: - 1500 - 15x + M == 0 2. Fosinio N& COSIO FB FB COS 10 10 NE sinio 10* Ck Ne 1 W Fc FB FA 1 NgsinIo 10 B NB NB COSID NA C - Nc NB COSO Y WB Na FBsino Ng sine AF FOCOSO N