176 CHAPTER 4 FORCE SYSTEM RESULTANTS *4-108. Replace the force system by an equivalent resultant force and couple moment at point O. Take F3 = {-200i + 500j - 300k} N. 1 Copyright 0 (2) F1=300 N x F3 4 1.5 m 1.5 m 4-110. Replace the force of F = 80 N acting on the pipe assembly by an equivalent resultant force and couple moment at point A. 400 mm B 300 mm 200 mm 200 mm 250 mm 2015 Pears F2 = 200 N Prob. 4-108 4-109. Replace the loading by an equivalent resultant force and couple moment at point O. Z 0 * 0.5 m 40° 30° F = 80 N Prob. 4-110 4-111. The belt passing over the pulley is subjected to forces F1 and F2, each having a magnitude of 40 N. F1 acts in the -k direction. Replace these forces by an equivalent force and couple moment at point A. Express the result in Cartesian vector form. Set 0 = 0° so that F2 acts in the -j direction. *4-112. The belt passing over the pulley is subjected to two forces F1 and F2, each having a magnitude of 40 N. F1 acts in the -k direction. Replace these forces by an equivalent force and couple moment at point A. Express the result in Cartesian vector form. Take 0 = 45°. z r = 80 mm V 300 mm 0.7 m F2= {-2i+5j-3k} kN 0.8 m F1 = {8i-2k} kN TA F Printed by Malcolm Mcmillan (mcmillan@phas ubc ca) on 8/11/2015 from 50.67.63.147 authorized to use until 12/4/2022, Use beyond the authorized user or valid subscription date represents a copyright violation.