F het = m¥2 net y x f = usN 1 r = radius of curvature of curve. N ? ? mg Force equations at maximum speed v, at threshold of sliding up incline. EFx = m - V 2 = N sin 0 + UN cos 0 r EFy = 0 = N cos 0 - Us N sin 0 - mg Solving this pair of equations for the maximum speed v gives:
A 4.0 m long steel beam is supported 3.0 m from a hinge by a cable attached as shown. LB : 65° FT = 150 N LT 40° De 40° Fg=mg If the tension in the cable is 150 N what is the mass of the steel beam? VG = ZU FT. LT = Fg. LB (150)(3 SM40)=(9.8 m) (25M(5°)
What is the acceleration of a 7.5 kilogram box on does not depend on mass a 19 degree friction less inclined plane? y FN mgy = mg cos O mgx = mg sin ? m EFx = max ?Fx ax m mg sin O ax m ax= g sin O X 19" mgy u = 0 mg ax= 9.8m/s2 x sin 1 9° a= 3.19 m/s2 mgx