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STAT1201 Analysis of Scientific Data Examination

Semester Two Examinations, 2023 STAT1201 THE UNIVERSITY OF QUEENSLAND AUSTRALIA This exam paper must not be removed from the venue Venue Seat Number Student Number Family Name First Name School of Mathematics & Physics Semester Two Examinations, 2023 STAT1201 Analysis of Scientific Data This paper is for St Lucia Campus students. Examination Duration: 120 minutes For Examiner Use Only Planning Time: 10 minutes Question Mark Exam Conditions: ·This is a Closed Book examination - no written materials permitted .Casio FX82 series or UQ approved and labelled calculator only .During Planning Time - Students are encouraged to review and plan responses to the exam questions .This examination paper will be released to the Library Materials Permitted in the Exam Venue: (No electronic aids are permitted e.g. laptops, phones) None Materials to be supplied to Students: Additional exam materials (e.g. answer booklets, rough paper) will be provided upon request. None Instructions to Students: There are 100 marks available on this exam from 5 questions. Write your answers in the spaces provided in pages 2-14 of this examination paper. Show your working and state conclusions, where appropriate. Pages 15-17 give formulas and probability values. Those pages will not be marked. If you believe there is missing or incorrect information impacting your ability to answer any question, please state this when writing your answer. Total Page 1 of 17 Semester Two Examinations, 2023 Formulas Basics 11 0-1 >)_0, - [ "+ Expected Values STAT1201 " E(I) = 1 [ ([ = [ )I &&&&&& &var I (I = [ )) I - E (I )+ &&&&&sd 8 var (I ) # # E(00 + 0 ) = DE (0) + 0 sd( 00 + 0 ) = |0 | sd(0 ) E( [$ + [. ) = E([$ ) + E([. )&&&&&var ) = var (Is ) + var (I ), &if&independent Standardising If&I&N&rmal([,] )&then&l = 0 1- 0 &~Normal(0,1) Binomial distribution E(1) = Il&&&&&&&s& Il (1 - 1 ) && && && & & & & & & & & sd ( 0(1 - 0) Tests and Confidence Intervals based on Standard Errors estimate - hypothesised &&&&&&estimate + 1'se(estimate) 0 = se(estimate) " " se([") =. V? + = 1-0 " 0-2 se(IU} ( Ju-IU &&&&&&se.y = ( + 151-1} 0 41-14 Page 15 of 17 Semester Two Examinations, 2023 Pooled -Test and Analysis of Variance I& = ([$ - 1 )[$ + (1. - 1 )0." Os + 0, - 2 STAT1201 SS SSG MSG DFT = 1 - 1&&&&&DFG = 1 - 1&&&&&&&&&&|"&&&&&&?R&&&&&& != DF SST MSR I = 0.05 Linear Regression ?,&&if&Group&A 1,&&if&Group&B = ' Odds and Logistic Regression 0 1-0 odds$for$group$B 0 odds = odds$for$group$A 1-0 Chi-Squared Tests expected overall&total (row&total) x (column&total) observed - expected )" 1 = expected df = (#rows - 1) × (#columns - 1) Signed-Rank Test 0(0 + 1) &&&&&&sa E( ) = 4 0(0+ 1)(21 + 1) & 24 Rank-Sum Test E(I ) = [$ ([$ + [. + 1) 2 &&&&&)&sd( Page