For the reaction shown, calculate how many moles of NH3 form when each amount of reactant completely reacts.
3N2H4(l) → 4NH3(g) + N2(g)
1. 5.1 mol N2H4
Express your answer using two significant figures.
2. 2.28 mol N2H4
Express your answer using three significant figures.
3. 5.7×10^−2 mol N2H4
Express your answer using two significant figures.
4. 9.19×10^7 mol N2H4
Express your answer using three significant figures.