00:01
So in this problem, for the situation that electron orbit around the center of mass in hydrogen atom, it is shown in this figure here.
00:12
So we have that r is equal to r -e plus rp, and the capital m is equal to the mass of electron plus the mass of proton.
00:24
And in the equilibrium, we have that m -e -r -e is equal to the mass of electron.
00:31
Equal to mp rp for the center of mass and that equal and we have that r e can be given by r minus rp so from rp will be m e divided by m .e divided by m .e plus m .p or m .r in the same way we can find that re will be mp or m time r that's for part a and for part b, we have that the kinetic energy of electron is 1 over 2 m .e.
01:09
Ve.
01:10
Where ve is given by r e omega.
01:14
And kp is 1 over to mp vp square or rp omega square.
01:21
So the total kinetic energy is ke plus kp.
01:27
And finally, it can be reduced to 1 over 2 m .e.
01:33
Mp over m .e plus m .e .r...