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(1) How much work is required to stop an electron $\left( m = 9.11 \times 10 ^ { - 31 } \mathrm { kg } \right)$ which is moving with a speed of $1.40 \times 10 ^ { 6 } \mathrm { m } / \mathrm { s } ?$

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$-8.93 \times 10^{-19} \mathrm{J}$

Physics 101 Mechanics

Chapter 7

Work and Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

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(I) How much work is requi…

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ssm How much work must be …

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An electron ($m = 9.11 \ti…

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(II) An electron $\left(m_…

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(a) How much work (expres…

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So here we're trying to calculate the work needed in order to stop in election. So the work needed here would simply be equal to the change in kinetic energy. This would be equal to 1/2 times the final squared minus V initial squared. And we know that the final squared is going to be zero in this case. Therefore, the work is going to be simply equal to negative 1/2 times the mass of an electron. So 9.11 times 10 to the negative, 31st kilograms times the initial velocity of the electron Ah, 1.4 times 10 to the sixth meters per second quantity squared. And we find that the work done on the electron ist negative 8.93 times 10 to the 19th. Sorry, Negative. 19th. Jules. Again, the work done is negative because we're trying to stop the electron and ah, native 8.93 times tense and they get 19th. Jules, that is our final answer. That is the end of the solution. Thank you for watching

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