00:01
We're given a set of parametric equations.
00:06
These are x equals the square root of t plus 1, and y equals the square root of t minus 1.
00:19
In part a, we're asked to find the cartesian equation of this curve by eliminating the parameter.
00:33
Well, notice that since x is equal to the square root of t plus 1, this implies that x squared is equal to t plus 1.
00:40
And therefore that t is equal to x squared minus 1.
00:51
So plugging this into our equation for y, which is the square root of t minus 1, we get the square root of x squared minus 1, minus 1, which is the square root of x squared minus 2.
01:10
Recognize that this is, of course, the equation for a hyperbola with equation x squared minus y squared.
01:27
Equals 2, but we have that x must be greater than or equal to root 2, and y is greater than or equal to 0...