Question
$12.5 \%$ of an isotope remains after 8 years from the initial stage. After 8 more years, the quantity present will be(a) $\frac{25}{16} \%$(b) $6.25 \%$(c) $0 \%$(d) $3.125 \%$
Step 1
According to the problem, $12.5\%$ of $I$ remains after 8 years. We can write this as: \[0.125I = I \times \left(\frac{1}{2}\right)^n\] where $n$ is the number of half-lives that have passed. Show more…
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