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16.6 Uniform Circular Motion and Simple Harmonic Motion(a)What is the maximum velocity of an $85.0-\mathrm{kg}$ person bouncing on a bathroom scale having a force constant of $1.50 \times 10^{6} \mathrm{N} / \mathrm{m},$ if the amplitude of the bounce is 0.200 $\mathrm{cm} ?$ (b) What is the maximum energy stored in the spring?
$V_{\max }=0.26568 \mathrm{m} / \mathrm{s}$$E_{\max }=3 \mathrm{J}$
Physics 101 Mechanics
Physics 103
Chapter 16
Oscillatory Motion and Waves
Periodic Motion
Wave Optics
Rutgers, The State University of New Jersey
University of Washington
Hope College
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so maximum velocity off oscillation is given by amplitude times, angular frequency amplitude and angular frequency square. With Cabe, I am on amplitude is given to us as 0.2 centimeters. So 0.2 times 10 power negative two meters square Rooter off K, which is 1.5 times 10 power six divided by the mass, which is 85 kilos. So let's do this calculation. So this gives me answer as zero point 26 57 meters per seconds. That that's the maximum velocity. And in the next part of the question, we are asked to find the maximum energy stored in the spring. The maximum energy E is equal to either maximum kinetic energy or maximum potential energy. So we know maximum kinetic energy because we know velocity. So how mass? Which is 85 times velocity, which is 0.26 57 squared. So let's do this calculation. Answer is just three dudes. So this is for the party. Thank you.
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