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$17-24=$ Logarithmic Form Express the equation in logarithmicform.$${ (a) }\ 3^{2 x}=10 \quad \text { (b) } 10^{-4 x}=0.1$$
a. $3^{2 x}=10 \leftrightarrow \log _{3} 10=2 x$b. $10^{-4 x}=0.1 \leftrightarrow \log _{10} 0.1=-4 x$
Algebra
Chapter 4
Exponential and Logarithmic Functions
Section 3
Logarithmic Functions
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Baylor University
University of Michigan - Ann Arbor
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but let's look at the procedure off changing from exponential form to logarithmic form first. So if I have the exponential form off A to the power off eggs equal to some B thing to change this into logarithmic form will have the log off and the base off the lock is the base off the exponents. So therefore it will be logged a and then the B goes into the log on the exponents, the eggs goes to the other the right hand side, and that is changing from exponential form to logarithmic form. So let's apply it to the question at A it is three to the power off to X equal to 10. So for the lock, the base will be the three and then the tin inside the lock and the two weeks as they explode, it comes down to the other side off the equation. Sign right Then at the it is 10 to the power off. Negative four X equal to zero comma one. So in the lock, the base is 10. Then this year Oh, come on. One equal to negative full eggs. Right. This can also be written as just lock off zero comma, one equal two negative four x Because if there's nothing, then we will assume that this is an invisible tin in the lock.
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