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$25-34=$ Evaluating Logarithms Evaluate the expre…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105

Problem 24 Easy Difficulty

$17-24=$ Logarithmic Form Express the equation in logarithmic
form.
$${(a) }\ e^{x+1}=0.5 \quad \text { (b) } e^{0.5 x}=t$$

Answer

a. $e^{x+1}=0.5 \leftrightarrow \ln 0.5=x+1$
b. $e^{0.5 x}=t \leftrightarrow \ln t=0.5 x$

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Chapter 4

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Section 3

Logarithmic Functions

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Video Transcript

but let's look at the procedure off changing from exponential form to logarithmic form first. So if I have the exponential form off A to the power off eggs equal to some B thing to change this into logarithmic form will have the log off and the base off the lock is the base off the exponents, so therefore it will be logged a and then the B goes into the log on the exponents. The eggs goes to the other, the right hand side, and that is changing from exponential form to logarithmic form. So let's apply it to the question at A it's given to us as e to the power off X plus one equal to zero Come on five. So let's look at the 1st 1 e. Ease the base off the experiment exponential form so it will become the base off the lock in this era come off five equal to X plus one. But remember that log E is the natural log, which I can change into Lynn off zero comma five equal to X plus one right b. It's given us e to the power off. Zero come off five X equal to T so again is my base. Then I have the key in the lock equal to zero comma five x. And because this is my natural log, I can rewrite this as Len off t equal to zero comma five x.

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