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Averell H.
Carnegie Mellon University

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97

Problem 15 Easy Difficulty

(1I) Calculate the average speed and average velocity of a
complete round trip in which the outgoing 250 $\mathrm{km}$ is
covered at 95 $\mathrm{km} / \mathrm{h}$ , followed by a 1.0 -h lunch break, and
the return 250 $\mathrm{km}$ is covered at 55 $\mathrm{km} / \mathrm{h}$ .

Answer

a. $61 \mathrm{km} / \mathrm{h}$
b. $\bar{v}=\Delta x / \Delta t=0$

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Video Transcript

So here we know that the, um for party we want to find the average speed. We know that the total distance traveled is going to be 500 kilometers and then we just simply need to find the total times The total distance traveled equals 500 kilometers. And then we can say that going there we can save the average speed or the average velocity would be equal to delta X of one divided by delta t someone we can solve For delta tease of one, this would be equal to delta X of one, of course, divided by the average velocity in the first portion of the trip. This is equaling 250 kilometres divided by 95 kilometers per hour. So this is giving us 2.632 hours for the second time. Delta T's up to this would equals Delta, except to which is again 250 kilometres on, divided by the east average velocity in the second portion. So this would be 250 kilometers divided by 55 kilometers per hour and this is giving us 4.5 for five hours Now There's a one hour lunch break so the delta T total would be equal to 4.545 Plus, what do you say for 4.545 plus 2.632 plus one So one hour lunch break and this is giving us 8.177 hours. So to find the average speed, this would be equal to Delta X Total divided by doubt the tee total and this would go 500 kilometers divided by 8.177 hours, giving us approximately 61 kilometers per hour. And then to find the for part B, we want to find the average velocity. However, the average velocity here, um, this is a round trip. So when you're when you're travelling round trip, you were you are ending up in the same place as you started. So your displacement, which defines velocity, will actually be zero. So if your displacement a zero your average velocity for the entire round trip would, of course be able to zero meters per second. That is the end of the solution. Thank you for watching

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