The formula for capacitors in series is given by $\frac{1}{C_{eq}} = \frac{1}{C_2} + \frac{1}{C_3}$. Since $C_2 = C_3 = 22.6 \mu F$, we can substitute these values into the formula to get $C_{eq} = \frac{C_2 C_3}{C_2 + C_3} = \frac{22.6 \times 22.6}{22.6 + 22.6} =
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