Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(1II) A bicyclist coasts down a $6.0^{\circ}$ hill at a steady speed of4.0 $\mathrm{m} / \mathrm{s} .$ Assuming a total mass of 75 $\mathrm{kg}$ (bicycle plus rider), what must be the cyclist's power output to climb the same hill at the same speed?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$610 \mathrm{W}$

Physics 101 Mechanics

Chapter 8

Conservation of Energy

Work

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

Cornell University

Simon Fraser University

University of Winnipeg

Lectures

04:05

In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

0:00

(III) A bicyclist coasts d…

01:55

02:06

05:18

03:46

71. (III) A bicyclist coas…

02:13

A bicyclist coasts down a …

01:47

01:22

(II) How fast must a cycli…

11:50

If a bicyclist of mass 65 …

06:03

ssm A bicyclist is coastin…

A cyclist in a race must c…

03:57

A bicyclist is coasting s…

07:28

08:59

A bicyclist of mass 75 $\m…

02:19

(III) A bicyclist of mass …

02:26

A bicycle and its rider to…

we start by drawing free body diagrams for the situation. So, uh, defined the A coordinate system such that uphill downhill is positive. XX is positive. X on, um, upwards is in the direction of the normal force. That's positive. Why, Okay, so when the cyclist is going down, uh uh, the force of gravity acts is a pattern. Angled data, obviously. But there's a normal force acting upwards, obviously, but the force affection is acting uphill. It's opposing the motion, right? So when the cyclist is going uphill Ah, this time gravity alone can't move the cyclist. So there's gravity force Ah, normal force and a four on Applied Force of Key. This is a force that will give us the power that we need a tow at the end of this problem. So this is acting up Hill and force infection. Opposing this motion is acting downhill on, So let's just simply resolve forces supply Newton's second law in the ex direction in both cases. So, for downhill motion, you have, uh, the event she at the horizontal component off force of gravity mg Scient, Ada minus the force of friction. FFr eyes equal to zero. Known that acceleration. Therefore, because he's going a constant speed. Therefore, the force of friction, um is mg signed a toe. Ah, here. You have, um f me minus the applied force minus force of fiction minus mg Signed data. Ah, this isn't, um or I should say negative d plus f far. Plus I'm decided a call. Zero. Therefore apply force is force affection plus mg signed data, and assuming is the same friction force acting on the bicycle cyclist system. We just replaced the force of friction from here. So you have mg Scient, Ada, plus some decent ada giving us two mg science data. Okay on then all we have to do is use the formula for power. Power equals force, times velocity. It's a constant speed. The cyclists traveling up. So this is two mg signed data times, feet and so plugging in values. We have 75 kilograms for mass times 9.8 meters per second squared for she times sign six degrees times velocity which is four meters per second giving us 610 watts of power. And that's it

View More Answers From This Book

Find Another Textbook

Numerade Educator

06:16

SafariEdit VietHistoryBcn-ManDevelopWindow Help4 [ &…

06:38

A neutral metal cube is placed distance d = 15 cm from dipole consisting of …

01:45

QUESTIONThe critical angle in air for particular type of glass 390 What …

What net external force (in N) is exerted on a 1050-kg artillery shell fired…

01:42

The shelf _ hanes from tha ceiling by two ropes (I and 2) Ablock of cheese B…

04:04

7.43 PM Tue Jun490 [98AnnotateEdit PDFFill & Sign

02:16

The figure shows a 30-kg boy sitting on one end of a 5.0 m long plank restin…

01:58

0 = 4583.5 30 = 3582.5 20 = 2581.5 1 0.50158…