00:01
All right, so we're given this system of linear equations here, 1 1ā2x plus 1 3rd y equals 2, and 1 5th x minus 2 thirds y equals 8, and we're allowed any method to solve this.
00:14
So i'm going to do this by substitution, and the substitution that i'm going to do here is going to look a little bit weird, but i promise you it is nice, and it will work out helpfully.
00:23
So we're going to have 1 3rds y equals 2 minus 1 1 1āx.
00:29
And so now that we've got this setup, one third y equals 2 minus 1 half, we can go ahead and substitute this into the other equation.
00:40
So we'll have 1 5th x minus, and so we actually have 2 times 1 3rd y.
00:48
So we'll have 2 times the 2 minus 1 1 1ā2.
00:56
See you already looking out kind of nice over here, which will give us 1 5x minus 4 plus x.
01:10
Equals 8.
01:14
So then what that's going to give us is this is going to give us 6 fifths x...