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22.6 The Hall EffectA large water main is 2.50 $\mathrm{m}$ in diameter and the average water velocity is 6.00 $\mathrm{m} / \mathrm{s}$ . Find the Hall voltage produced if the pipe runs perpendicular to the Earth's $5.00 \times 10^{-5}-\mathrm{T}$ field.

The Hall voltage is $7.50 \times 10^{-4} \mathrm{V}$

Physics 102 Electricity and Magnetism

Chapter 22

Magnetism

Magnetic Field and Magnetic Forces

Sources of Magnetic field

Electromagnetic Induction

Inductance

Rutgers, The State University of New Jersey

Simon Fraser University

Hope College

University of Winnipeg

Lectures

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so we can cap calculate epsilon, which would be the whole voltage. This should be the magnitude of the magnetic field of earth Times l which in this case would be the diameter and V would be the velocity of water. And so this is equaling 5.0 times 10 to the negative fifth. Tesla's and well supplied by the diameter of 2.50 meters multiplied by 6.0 meters per second. And we find that the whole voltage is going to be equaling 7.50 times 10 to the negative fourth volts. This would be our final answer. That is the end of the solution. Thank you for watching.

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