00:01
Now this problem we've been given the equation x squared plus xy plus y squared is equal to three and we would like to find an equation of the tangent line at the point 1 comma 1 1.
00:16
Now in order to find the equation in the line we need to know two things we need to know a point that it goes through and the slope well, we've already been given the point here and so we just need to find the slope and so for problems like this that means finding the derivative as we need to use implicit differentiation so the derivative of x squared is 2x.
00:38
The derivative of xy using the product rule derivative x is 1.
00:40
So we have 1 times y.
00:43
Plus the derivative of y is y prime times x.
00:48
Derivative of y squared is 2y times y prime.
00:53
And then the derivative of 3 is 0.
00:57
Now we'll keep our y primes here on the left, but we will pull the y prime out.
01:01
And we'll just with x plus 2y.
01:04
And we'll take the 2x plus 1, 1y over the other side...