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$25-34=$ Evaluating Logarithms Evaluate the expression.$$\begin{array}{lll}{\text { (a) } \log _{3} 3^{7}\ { (b) } \log _{4} 64} & {\text { (c) } \log _{5} 125^{}}\end{array}$$

$=3$

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 3

Logarithmic Functions

Campbell University

McMaster University

Harvey Mudd College

University of Michigan - Ann Arbor

Lectures

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$25-34=$ Evaluating Logari…

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01:18

Evaluating Logarithms Eval…

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Evaluate the expression.

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Evaluate each expression.<…

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Rational Exponents Evaluat…

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Exponential Form Express t…

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Simplify each exponential …

in this question, we're going to make use off to logarithmic rules. The 1st 1 state that if the base and the value or the same, then the whole log becomes one, right? The other rule that we need here is that lock off a base A with the value B to the power off. See will become. See Look a be right. So take note If this when these two are the same, then the whole lock becomes one. When I have the value to an exponents, the exponents goes, multiply in front and you still have the lock off a B. They fought at a We have log 33 to the power of seven. So according to the second rule that we used chair, the seven can multiply in front. Then the first rule states that the three of the three if there are the same, that becomes one and the in Sudanese saving. So for Locke, Base four off 64 the 64. So I'm not always going to go to Brian practice, right, Because we have a full in the base. I would like to change the 64 order to four to the bar off something which is three Now the three can multiply in front and according to the first rule that is equal to one which simplifies to three. Right when we have look off based, 525 then I can rewrite the 125 in its prime. Factors off. Five. Cute. So now the three can multiply in front and I'm left with Lof based 55 which I know now it's one equal to that equals 23

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