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$25-34=$ Evaluating Logarithms Evaluate the expre…
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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105

Problem 27 Easy Difficulty

$25-34=$ Evaluating Logarithms Evaluate the expression.
$$\begin{array}{lll}{\text { (a) } \log _{6} 36^{}\ { (b) } \log _{9} 81} & {\text { (c) } \log _{7} 7^{10}}\end{array}$$

Answer

$=10$

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Algebra and Trigonometry

Chapter 4

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Section 3

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Video Transcript

in this question, we're going to make use off to logarithmic rules. The 1st 1 state that if the base and the value or the same, then the whole log becomes one, right? The other rule that we need here is that lock off a base A with the value B to the power off. See, will become. See Look a be right. So take note If this when these two are the same, then the whole lock becomes one. When I have the value to an exponents, the exponents goes, multiply in front and you still have the lock off a B. So for the 1st 1 in log 6 36 we can really want the 36 as six to the power off to six square and now, from the second through, the two can multiply in front and we have left Log off by 66 which we've seen from the first rule is equal to one the whole, off the whole log. So that gives us two. All right. At B, we have the log off nine. 81. So the basis nine and we have 81. So in this case, we can relight the 81 as nine squeak, taking the to to the front, multiplying it with the whole log. Then we see that Locke based 99 is one again from the first room and that also end up to be to Then we have log, see even by 77 to the power off 10. So now the team can multiply in front and we still have by 77 in the lager of them. On that end, up to be one again And the answer East thing 10.

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